Algebra question
What is the solution to x + 1?
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-1 0 -
quote:Originally posted by fugawe
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WHAT!!!?!?!?!?0 -
All real numbers. 0 -
y 0 -
There is no solution. It's an expression, not an equation. 0 -
Boy, I'm sure glad I don't sit next to any of you guys in class!! But seriously, the wife is taking classes online, and we got into this big discussion concerning the answer to x+1. I say that x+1 is as low/small as you can work this problem. My know-it-all 18 yr old daughter says its 1x. Which to that I say is multiplying them. 0 -
quote:Originally posted by mlincoln
There is no solution. It's an expression, not an equation.
This isn't philosophy![;)]0 -
I would have said the answer is 1x like your duaghter said. But I failed algebra.....twice. 0 -
quote:Originally posted by matwor
What is the solution to x + 1?
Bismark or 12150 -
1X + 1[:D]
And yes, 1X would be multiplying the two.
Ben0 -
quote:Originally posted by LaidbackDan
quote:Originally posted by matwor
What is the solution to x + 1?
Bismark or 1215
...................or history0 -
none 0 -
X is a variable and 1 is a set value. It's just an expression. 0 -
I am not interested in the solution, I want to find out what is in teh precipitate 0 -
quote:Originally posted by matwor
Boy, I'm sure glad I don't sit next to any of you guys in class!! But seriously, the wife is taking classes online, and we got into this big discussion concerning the answer to x+1. I say that x+1 is as low/small as you can work this problem. My know-it-all 18 yr old daughter says its 1x. Which to that I say is multiplying them.
Catpealer's got the best answer: all real numbers. Except I think you can map x to an imaginary number....at which point x + 1 is completely unconstrained.
Your know-it-all 18-yr-old is wrong. x+1 = 1x only if x = infinity (positive or negative)--and even then I think it's a shaky argument.
If by saying 'x+1 is as small as you can work this problem,' you mean that the expression can't be simplified without further information about x, then you're right.
mlincoln and Slow_Hand are also right: it is just an expression.0 -
True 0 -
x + 1 = all real numbers
just as CP said. There is no definite answer.
x in this case is a variable.
From the expression above, "all real numbers" is the correct answer.0 -
quote:Originally posted by spurgemastur
yyep. in the expression "X+1", you are saying "unknown variable X plus 1", which still equals an unknown variable. so Y it is.
X+1=Y0 -
x+1 is equal to or lesser than ((x+2)-1)*1 0 -
... here's an expression (.....) ... oh wait, I can't do that, it'll get "P[}:)][}:)]F"ed. 0 -
Does it matter? Don 0 -
Simple: X + 1 is the mathematical expression of a twice divorced person.[:D] 0 -
quote:Originally posted by spurgemastur
quote:Originally posted by matwor
Boy, I'm sure glad I don't sit next to any of you guys in class!! But seriously, the wife is taking classes online, and we got into this big discussion concerning the answer to x+1. I say that x+1 is as low/small as you can work this problem. My know-it-all 18 yr old daughter says its 1x. Which to that I say is multiplying them.
Catpealer's got the best answer: all real numbers. Except I think you can map x to an imaginary number....at which point x + 1 is completely unconstrained.
Your know-it-all 18-yr-old is wrong. x+1 = 1x only if x = infinity (positive or negative)--and even then I think it's a shaky argument.
If by saying 'x+1 is as small as you can work this problem,' you mean that the expression can't be simplified without further information about x, then you're right.
mlincoln and Slow_Hand are also right: it is just an expression.
if X+1=1X, then subtract X from both sides, and you get 1=0 so that can't work.
X+1 can be "all real numbers", also it can be any imaginary number if you put a complex number in as X. (a complex number is any term involving i, or the square root of -1) so really the term "X+1" can equal anything. which evaluates to an unconstrained variable. call it Y.0 -
As stated:
x+1
x can be anything, all real numbers, imaginary numbers, some logic expression, the number of bong hits...anything. At stated it is only the grounds for a philosophical discussion. Now if we complete the statement to x+1=y and define y then we can solve.
Staying away from the philosophical discussions the best solution for the problem is that x=y-1.0 -
x + 1 = 1 + x 0 -
quote:Originally posted by matwor
What is the solution to x + 1?
666 [}:)]0 -
When I was in college the answer was beer. Then again, when I was in college the answer to everything was beer.[:I] 0 -
quote:Originally posted by matwor
What is the solution to x + 1?
+1[:D]0 -
Quote: I say that x+1 is as low/small as you can work this problem. My know-it-all 18 yr old daughter says its 1x. Which to that I say is multiplying them.
x+1 is not a problem, so there is no solution.
For your daughter's benefit..
1x is multiplication as you told her. In this case 1x=x. So 1x is not equal to x+1. It's equal to (x+1)-1.[:D]0 -
x+1=x+1 0
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