trajectory of the .223
How much drop can one expect @ 300 yds? 500 yds?
Using a AR 15 20" barrel 69gr
Using a AR 15 20" barrel 69gr
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What's your bullets BC and your ACTUAL muzzle velocity?
What is your zero distance?
If you zero at 300yd, than your drop at 300 will be zero.0 -
Try here, this will give you a good idea, of all cals & distances.
http://www.remington.com/products/ammunition/ballistics/0 -
quote:Originally posted by johnstlucie
How much drop can one expect @ 300 yds? 500 yds?
Using a AR 15 20" barrel 69gr
Impossible to answer without knowing your zero and your muzzle velocity (which will depend a bit on the exact load used).
Other factors that would be relevant at extreme distances (though to a lesser extent) would be the ballistic coefficient of your particular bullet, temperature and humidity.
But as a first approximation, using a standard 200 yard zero, and a standard 69 grain load at 3000 fps muzzle velocity, you should expect roughly a 7.5 inch drop at 300 yards and a 45 inch drop at 500 yards.
The best way to confirm this, of course, is to take your actual gun with your actual load, and measure the actual drops over precisely measured distances.
Needless to say, in the "real world" compensating for a 45 inch drop isn't trivial, and small errors in range estimation can lead to significant differences in drop distance.0 -
Try one of the ballistics calculators such as that found at hornady.com. You can input a wide variety of assumptions and zero yardage, etc. 0 -
quote:Originally posted by Barzillia
All objects which are acted upon by gravity will, excluding all other factors, accelerate towards the center of the earth at a velocity of 32 feet per second/per second when released.
For any object in motion, the distance traveled may be calculated by speed/time.
Hence, for an object in a vacuum traveling at 2,000 feet per second in a flat trajectory and tangent to the earth's surface, in one second and at a distance of 2,000 feet, the object would have also fallen 32 feet.
However, in actuality the projectile will be continuously slowing due to wind resistance, hence taking progressively longer to travel the same distance, and the acceleration of gravity is cumulative.
Presuming that in order to travel the entire distance to the intended target it will be necessary to first travel half that distance, and first half of that distance, and so on, it becomes obvious that no projectile will ever reach any target at any speed and the universal force of gravity will accelerate the projectile towards the center of the earth in an inevitable course of catastrophe.
Accordingly, I would never fire the gun.
[;)]
I drink I need a think.[:D]0 -
johnstlucie,
We can't give you an exact figure. but since you are quoting a 20" barrel with an AR, I will assume the load is standard 3000 fps. Also starting with the standard AR 25m zero (27.5 yds.). BC, temp, humidity, wind etc. really won't start to affect bullet drop/rise until around 300 yds. so they are pretty much a non-factor.
So, zeroing that way gives you a max trajectory height @ 130 yds. of 2.7" @300 yds. you are 5.1" low and 500 yds. you are 41.5" low.
Zeroing @ 100 yds. gives you a max trajectory height @ 100 yds. and you are 12" low @ 300 and 53" low @ 500.
Zeroing @ 300 yds. gives you a max trajectory height @ 170 yds. of 5.3" and of course 0" @ 300 and 33" low @ 500
Zeroing @ 500 yds. gives you a max trajectory height @ 280 yds of 20" and 10.5" high @ 100 and 19.5" high @ 300. And, again 0 where zeroed.
EDIT:
What I gave you was a standard published load in standard conditions. Your loads in your rifle may vary so you will have to go out and shoot it to see where it hits at the various distances.0
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