Smith & Wesson Model 1 3rd issue question

rossowmn

December 06, 2012 02:56

I recently found a Model 1 3rd Issue S&W revolver. On most (but not all) photos of the same gun online I see a rod that extends under about half the length of the barrel. The gun I have has only a stub -- maybe 3/16th" -- instead of the longer rod. The stub hasn't been broken off -- the end has been machined perfectly flat, with a delicate chamfer around the edge. My question: Is the rod I see in pictures a casing-removal rod? If so, how did it stay in the gun -- screw in or some other way? I'll appreciate any advice.

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  MIKE WISKEY

  December 06, 2012 04:22

  " My question: Is the rod I see in pictures a casing-removal rod? If so, how did it stay in the gun -- screw in or some other way? I'll appreciate any advice."............From my (limited) understanding the rod stays in place and you remove the cylinder, revers it and use the rod to 'poke' the casings out.

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  BigLoop22

  December 06, 2012 05:02

  rossowmn,
  
  As MIKE WISKEY said, that rod is a fixed rod:
  
  http://www.gunbroker.com/Auction/ViewItem.aspx?Item=318685777
  
  
  
  
  
  You remove the cylinder, turn it around, and you push the individual chambers over it, to eject the empty shells, one-at-a-time.

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  rossowmn

  December 06, 2012 15:54

  Thanks for the information. The fixed-rod idea now makes sense to me. What I have to figure out next is how to get the little stub out so I can put in a replacement ejector rod. The stub's not held with the screw -- too short -- so it's either glued in (no sign of that) or a driven-in force fit. I may have to carefully chuck the gun into a vise and drill the rod enough to get an easy-out or something in to try to work it loose. (Do I feel a disaster in my future?[:0])

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