deflection
Herei s a formula from the Marine's sniper school. 200 yards divided by 100 = 2; 2 times 10 mph wind = 20 divided by 13 constant, = 1.53 MOA or 3.06 wind drift in a 10 mph wind.
1/100 x mph
______________ = MOA
13 (constant)
1/100 x mph
______________ = MOA
13 (constant)
0
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This looks like a handy rule of thumb, but I'm afraid I don't quite understand the formula as written.
Are you saying, in effect, that bullet wind drift is about 1.5 inches per 100 yards per 10mph crosswind?
Presumably this is for a 7.62x51 NATO/ .308 Winchester or similar round (eg 30-06) right?0 -
If you are on the line, things are getting squirrelly, and time is running out, just try doing the math in your head and let us know how it turns out.
Why not run a ballistic table with your bullet BC and velocity, using a couple of different wind speeds, print it out and tape it to your stock?
JMHO
Ray0 -
Yes, 1.5 MOA in 200 yards. That is 3 inches 0
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