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Wind Drift Inconsistency

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4 comments

  • Mobuck
    My thoughts?
    The wind doesn't "turn" the bullet as if you turned the steering wheel of a car. It "pushes" on the up wind side of the bullet and creates a slight vacuum on the downwind side of the bullet causing the bullet to "drift" laterally but on the same directional vector.
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  • cbyerly
    A review of the NRA high power shooting record book should answer most of your questions on wind drift. There are tables for most popular long range cartridges.
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  • Cheechako
    First of all, it's wind deflection, not drift. A bullet will turn to follow the wind, not drift with it or be pushed by it. Once you understand and accept that simple principle of physics, it all becomes much clearer. Unfortunately, many shooters understand the principle but refuse to accept it.

    Second, think of wind deflection in minutes of angle, not inches.

    The wind nearest the muzzle is much more important that one near the target. Any deflection near the muzzle will still be present at the target (no matter how far away it is) unless something happens to change or reverse the deflection. In you first example, if the bullet is deflected 5 moa at 100 yards (5 inches), it will have the same 5 moa deflection at 500 yards (25 inches), or at 1000 yards (50 inches), or any other distance.

    In your second example, the bullet is deflected 5 inches, but this time the deflection is at 500 yards, which is only 1 moa. So the deflection at 100 yards would be 0 moa, and at 1000 yards it would still be 1 moa (10 inches).

    In your last example, the bullet is deflected 5 inches at 100 yards (5 moa) but it has turned to follow the wind, so if the wind is still present all the way to the target, there will be an additional deflection. If a bullet was pushed by the wind, or drifted with it, the accumulative effect would be so great that we'd have one helluva time hitting a 1000 target in a steady 25 mile an hour side wind.

    External ballistics requires an open mind and, more importantly, an acceptance of Mother Nature's rules of physics. The rules sometimes seem to defy logic but once you realize that they cannot be bent or broken you are on your way to understanding. And, it helps to forget the comparisons with a swimmer in a river, an airplane flying in the wind, and a golf ball in flight. Examples like those only make it more confusing.
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  • beantownshootah
    I think this source makes it easy (or easier) to understand.

    http://www.shootingtimes.com/2011/06/03/dont-blow-a-shot-in-the-wind

    In short, a crosswind doesn't just blow a bullet sideways knocking it a fixed amount off target. Instead it deflects the bullet off its original flight path, changing the angle of the shot away from the shooter.

    The problem with the original question, is that it overstates the effect of wind drift at short distances.

    A 10mph crosswind will deflect a typical .308 bullet about 1 inch (or better yet, 1 MOA) at 100 yards, not 5 inches! If the wind stopped at 100 yards, then the bullet would hit a 500 yard target off from point of aim by about 5 inches.

    Per the tables, a continuous 10mph wind would be expected to move the same .308 bullet about 22 inches at 500 yards. By extrapolation, a continuous 25mph crosswind would be expected to move the same bullet about 55" at 500 yards. To hit your target, you'd have to adjust your point of aim towards the wind by about 4.5 feet.

    If that sounds like a lot, it is, but note that a 25mph wind is actually quite brisk. Its a "strong breeze" on the Beaufort scale, meaning you'll hear a whistling sound from overhead wires, and find it extremely difficult to hold/use an umbrella. EG:

    http://www.youtube.com/watch?v=gI9JC4xxsic

    Note also that bullets slow down normally during flight. As a result, the effect of wind is greater on bullets further away from the shooter, meaning that the RATE of change of direction of the bullet also increases the further it gets from the shooter.
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